Physics clarification, no numerical answer required.? - there is a minimum numerical value
You are stuck behind a slow driver, there is a 1-km long, slow to between a car and a truck. To deliver to slow down at least 40 meters from the vehicle. Travel 70km / h and a truck traveling at 80 km / h. Each car is 4 meters long. What is the minimum acceleration is required.
Here you will find the definitive answer is not the problem that only the manipulation of the equation could be found to take the maximum time to them. I do not understand how this works, I can have someone vt step by step, how to convert d =:
d = V (auto) t + d + V (HGV), t
The numerical values
1.000 m = 19.44 (t) + 44 + 22.22 (t)
956m T = (19.44 + 22.22)
1 comment:
The truck from the opposite direction and was 70 + 80 = 150 km / h = 0.0417 kilometers / s
To reach 40 meters in front of the car before the car must be 40 + 4 m speed in front of another vehicle when it begins when the next car is slow. The distance they have at time t is 44 m. The car cover comes in the opposite direction in 1000 to stay at 44 meters per hour or 0.956 kilometers. He covered the distance in 0.956/0.0417 = 23 sec.
Your vehicle must u0026lt in 44m \\ \\ Travel \\ \\ \\ \\ \\ \\, is 23 sec, and the formula S = 0.5 * a ² * T 44 = 0.5 * A * 23 ² a ² = 88/23 = 0.17 m / s ²
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